Problems Based on Time
Time = 2 / 11 (A₁ +/- A₂ )
Here, A₂ = Given Angle
A ₁ = Smaller Number * 30
The value of time is ( in minutes ) and must lie between 0 and 60.
Therefore, 0 greater than 2 /11 * (A₁ +/- A₂ ) less than 60
FOOD FOR THOUGHT :
0 ° and 180 ° are the two angles which don't form at all between the duration of 1 Hour .
Any angle forms twice between the duration of 1 hour.
Once the angle forms before the coinciding of the Minute and Hour hand .
Second time , it forms after the coinciding of the Minute and Hour Hand .
Exception, some angle forms twice after the coinciding while sometimes it forms before coinciding.
Q 1. At what time between 7 and 8 O’clock are the hands at an angle of 45 ° ?
Sol : Here A₁ = 7 * 30 = 210 ° and A₂ = 45 °
Time = 2 / 11 ( 210 +/- 45 )
Case 1 : While Adding Case 2 : While Subtraction
Time = 2 / 11 ( 210 +45 ) Time = 2 / 11 ( 210 -45 )
= 2 /11 ( 255 ) = 2 / 11 ( 165 )
= 510 / 11 = 2 * 15
= 46 4 /11 = 30
Hence, the answer is at 7 : 30 and at 7 : 46 4 /11 , the angles are at 45 ° between 7 and 8 O’clock .
Q 2. At what time for the first time between 5 O’clock and 6 O’clock are the hands at an angle of 95 ° ?
Sol : Here A₁ = 5 * 30 = 150 ° and A₂ = 95 °
Time = 2/11 (150 +/- 95 )
Case 1 : While Subtracting
Time = 2/11 * ( 150 -95 )
= 2/ 11 * ( 55 )
= 2 * 5
= 10
Hence, at 5 : 10 there is an angle of 95 ° between 5 O’clock and 6 O’clock .
Q 3. At what time between 5 : 30 and 6 O’clock are the hands at an angle of 70 ° ?
Sol : Here A₁ = 5 * 30 = 150 ° and A₂ = 70 °
Case 1 : While Addition
Time = 2/11 * ( 150 + 70 )
= 2/ 11 * ( 220 )
= 2 * 20
= 40
Here, we only have to do the Addition because we need to calculate the value after 5 : 30.
If we calculate the value by subtraction, the value obtained is less than 5 : 30.
Q 4. At what time between 3 O’clock and 4 O’clock is the minute hand 7 minute away from the hour hand ?
Sol : Speed of minute hand is 6° / minute .
According to the question, the minute hand is 7 minutes away from the hour hand.
Therefore, For & minute = 7 * 6° = 42 ° .
The desired angle is 42 ° .
So, Here A₁ = 3 * 30 = 90 ° and A₂ = 42 °
While Addition
Time = 2/11 * ( 90 + 42 )
= 2/ 11 * ( 132 )
= 2 * 12
= 24
At 3 : 24 , the minute hand is 7 minute away from the hour hand.
Q 5. At what time between 3 o'clock and 4 o'clock is the minute hand 4 minutes behind the hour hand?
Sol : Speed of minute hand is 6° / minute .
According to the question, the minute hand is 4 minutes away from the hour hand.
Therefore, For & minute = 4 * 6° = 24 ° .
The desired angle is 42 ° .
So, Here A₁ = 3 * 30 = 90 and A₂ = 24 °
While Addition
Time = 2/11 * ( 90 - 24 )
= 2/ 11 * ( 66 )
= 2 * 6
= 12
At 3 : 12 , the minute hand is 4 minute away from the hour hand.
Ask me in the comment section, if you face any problem while solving clock aptitude questions. Visit next page for more clock problems.
Comments
Post a Comment