Skip to main content

CLOCKS ( SPECIAL ANGLES )

Special Angles (0 ° and 180 ° and 90 ° )


FOOD FOR THOUGHT : 0 ° and 180 ° are the two angles which don't  form at all between the duration of 1 Hour.

  1. For 0 ° : (i.e. between 11 ‘O Clock to 12 ‘O Clock and Between 12 ‘O Clock to 1 ‘O Clock ). During this duration, only one time both the Hands coincides  sharp at 12 ‘O Clock.

  2. For 180 °  : ((i.e. between 5 ‘O Clock to 16 ‘O Clock and Between 6 ‘O Clock to 7’ O Clock ). During this duration, only one time both the Hands are opposite to each other sharp at 6 ‘O Clock.


Q 1. How many times are the hands together in a day ?

Sol :  In Hour = 1 time.

          In 12 hours = 12 - 1 = 11 times

         Between 11 'O'Clock to 1 ‘ O'clock, the time duration is 2 Hours. But the hands  coincide at

one time only i.e. right  at 12 ‘ O Clock. Therefore,In 12 hours Duration Hands coincide 1 time

less  in the complete duration of 12 hours.

       

Similarly,   In 24 hours = 22 times Hands coincides. (Forms 0
° angle )


Q2. How many times are the hands opposite each other in a day ?

Sol : In 1 hour = 1 time

         In 12 hours = 12 - 1 = 11 time

        Between 5 'O'Clock to 7 ‘ O'clock, the time duration is 2 Hours. But the hands are opposite to

each other  at one time only i.e. right  at  6‘ O Clock. Therefore,In 12 hours Duration Hands are

1 time less at 180 ° in the complete duration of 12 hours.

 Similarly,   In 24 hours = 22 times Hands coincides. (Forms 180 ° angle )


Q3. How many times are the hands be right angled in a day ?

Sol : In 1 hour = 2 times. 

        In 12 hours = 24 - 2 times = 22 times           (At 3 ‘O clock and 9 ‘ O clock , only 1 time right angle forms.  At sharp 3 ‘ O clock and 9’ O Clock only.)

        In 24 hours = 48 - 4 times = 44 times 


Q 4. How many times are the hands together from 10 am to 3 pm ?

Sol : No. of Hours from 10 am to 3 pm. = 5 hours

        No. of times coincide = 4 times                     (12 O’Clock is included)


Q 5.  How many times are the hands together from 5 : 30 pm to 9 : 30 pm ?

Sol :  No. of Hours from 5 : 30 pm to 9 : 30 pm. = 4 hours

         Between 5 to 6 pm. = the hands coincide before 5 : 30

         Between 9 to 10 pm. = the hands coincide after 9 : 30

         Hence we need to check the duration 6 pm to 9 pm  = 3 hours

         No. of times coincide = 3 times                     (12 O’Clock is not included)


Q 6. How many times are the hands opposite to each other  from 10 am to 4 pm ?

Sol :  No. of Hours from 10 : 00 am to 4 : 00 pm. = 6 hours

         No. of times opposite to each other = 6 times.          (Because 6 O’Clock is not included.)



Q 7. How many times are the hands opposite to each other  from 4 pm to 10 pm ?

Sol :  No. of Hours from 4 : 00 pm to 10 : 00 pm. = 6 hours

         No. of opposite to each other = 6 - 1 = 5 times.       (Because 6 O’Clock is included.)


Q 8. How many times do the hands coincide and  opposite to each other  from 11 am to 5 pm ?

Sol :  Coincide : No. of Hours from 11 : 00 am to 5 : 00 pm. = 6 hours

         No. of times coincide = 6 - 1 times                     (12 O’Clock is included)

         Opposite to each other :  No. of Hours from 11 : 00 am to 5 : 00 pm. = 6 hours

          No. of opposite to each other = 6  times.       (Because 6 O’Clock is not included.)


Q 9. How many times are the hands be in a straight line for Sunday 5 PM to Monday 7 PM ?

Sol : FOOD FOR THOUGHT : Straight line = 0 ° (coincide) and 180 ° (opposite to each other)                                       (Mistake committed by students in the exam frequently.)

No. of Hours from Sunday 5 PM to Monday 7 PM. = 24 hours + 2 hours

     HANDS COINCIDE  

 No. of Hours from Sunday 5 PM to Monday 5 PM = 24 hours = 22 times

       Between 5 PM to 7 PM = 2 hours = 2 times        (Because 12 O’Clock is not included.)

HANDS OPPOSITE TO EACH OTHER

No. of Hours from Sunday 5 PM to Monday 5 PM = 24 hours = 22 times

Between 5 PM to 7 PM = 2 hours = 1  time          (Because 6 O’Clock is included.)

No of times = (22 + 1 ) +( 22 + 2 ) = 24 + 23 = 47 times

       Hence the answer is 47 times hands be in a straight line. 


Q 10. How many times are the hands at right angles from 1 pm to 5 pm ?

 Sol : No. of Hours from 1 : 00 pm to 5 : 00 pm. = 4 hours

     No of times Right angle forms from 1 : 00 to 5 : 00 = 2 * 4 - 1 = 8 - 1 = 7 times. 

   (Because 3 PM is included in the duration)


Q 11. How many times are the hands coincide, opposite to each other and are  at right angles from 5 pm to 11 pm ?

Sol : No. of Hours from 5 : 00 pm to 11 : 00 pm. = 6 hours

No. of times Hands coincides = 6 times                            (Because 12 O’Clock is not included.)

No.of times Hands  Opposite to each other = 6 - 1 = 5 times    (Because 6 O’Clock is included.)

No of times Hands are at right angle = 2*6 - 1 = 12 - 1 = 11 times

  (Because 9 PM is included in the duration)

 

Q 12. How many times are the hands coincide, opposite to each other and are  at right angles from 2 pm to 10 pm ?

Sol : No. of Hours from 2 : 00 pm to 10 : 00 pm. = 8 hours

No. of times Hands coincides = 8 times                            (Because 12 O’Clock is not included.)

No.of times Hands  Opposite to each other = 8 - 1 = 7 times       (Because 6 O’Clock is included.)

No of times Hands are at right angle = 2*8 - 2 = 16 - 2 = 14 times  

(Because 3 PM and  9 PM is included in the duration)


Ask me in the comment section, if you face any problem while solving clock aptitude questions. Visit next page for more clock problems.


Comments

Popular posts from this blog

Digital Sum Balance (D.S.)

A single digit is obtained by adding all the digits of a number is called Digital Sum Balance (D.S.)   Ex :  12 → 1 + 2 → 3 24 → 2 + 4 → 6 21 → 2 + 1  → 3 9876 → 9 + 8 + 7 + 6 → 30 → 3 + 0 → 3 3452 → 3 + 4 + 5 + 2 → 14 → 1 + 4 → 5 Or,  On Dividing the digits by 9, the obtained Remainder is Digital Sum Balance.  Ex :    12    ━━ = 3                9      24 ━━━ = 6      9    3452 ━━━━ =  5      9 KEY HIGHLIGHTS : The range of D.S. always falls from 0 to 9. When we add 9 to a number, its Digital Sum will not change therefore in order to calculate Digital Sum we need to cancel out  all the 9’s.  9 + 1 → 10 → 1 9 + 2 → 11 → 2 9 + 3 → 12 → 3 9 + 4 → 13 → 4 9 + 5 → 14 → 5 9 + 6 → 15 → 6 9 + 7 → 16 → 7 9 + 8 → 17 → 8 9 + 9 → 18 → 9 Example : 123 45 → 6 → Digital Sum ...

HCF and LCM

HCF and LCM FACTORS / DIVISORS = Numbers that divide any number completely, without leaving any Remainder are its factors. Example : Factors of 72 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72.                    Factors of 90 are 1, ,2, 3, 5 , 6, 9, 10, 15, 18, 30, 45, 90 MULTIPLES =   Numbers that fall in tables of any given number are its Multiples. Examples  : Multiples of 12 are 12, 24, 36, 48, 60, 72, 84, 96……                       Multiples of 5 are 5, 10, 15, 20, 25, 30, 35, 40, 45, 50 ….. HIGHEST COMMON FACTOR (H.C.F.) /  GREATEST COMMON DIVISOR (G.C.D.) =   Largest number that divides two or more than two given numbers. Examples : Calculate the  H.C.F. of 45 and 27  Sol : Factors of 45 = 1, 3, 5, 9, 15, 45       ...

Number System (No. of Zeros)

  How to Find Number of Trailing     Zeros in a Factorial or Product Under the topic of Number of Zeros , it is expected to find out the number of trailing zeros at the end of the number. In simple words, it can be said that to calculate the No. of Zeros at the  right side of the number. To make the things more clear, let us take a simple example to understand the concept of Number of Zeros Example : 1234057000 → No. of Trailing zeros →  3                  1050500000 → No. of Trailing zeros → 5                  1.5 x 10⁵ → No. of Trailing zeros → 4 Such Zeros that are represented at the end of the numbers are actually the Trailing Zeros. Now the next thing arises about the formation of Zeros in the Numbers. So, the fundamental regarding the formation of a Zero is the presence of a Pair of ...